Range Calculation.

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AA Action Electric.

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Location
Fort Myers, FL
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Electrical Contractor
I am practicing calculations for my UE license in FL and I am struggling with a practice question that I think I have right and the book has wrong. Can you guys help me out?

Q. What is the maximum demand in KW for one 8KW range and one 12KW range in a dwelling.

My answer is 16.2KW I calculated the first 8KW from row 2 column B at 65% because were talking about 2 separate appliances. Then I calculated the 12KW from line 2 column C at 11KW because theres 2 ranges.

65% or 8KW = 5200w + the 11,000W = 16.2KW.

The answer sheet does all the calculations from row 1 as one appliance. 80% of 8KW = 6400w then column c row 1 equals 8,000w for the 12KW range and the correct answer according to the answer key is 14.4KW which I disagree.

Is it 16.2KW or 14.4KW?
 
I agree with the answer key.

A 12 kw range is 8kw since there is only 1 12 kw range and 8kw times 80% (6400) so you know the rest

ans. 14,400 or 14.4kw
 
Actually you can use 2 ranges if you add the 12 kw and 8kw = 20 kw then multiply by 65% (Col.B- for 2 ranges)

20 x .65 = 13kw but I have never seen a test accept that as an answer
 
curt swartz said:
Dennis, what would be the load for (2) 12kw ranges
Click to expand...

Thanks @curt swartz ---You are correct. My post in #6 I had backwards. You could use 2 ranges at 12kw and get 11 kw as your answer but again most test don't give that as an answer.

Sorry @AA Action Electric.

Col C allows up to 12KW which means you could use the 8kw range at 12kw and then you have 2 12kw ranges. In that case 11 kw is correct. My guess is their answer, as well as other test authors, are trying to get you to use 2 columns but their answer is incorrect.

On an exam I would try it both ways and see which has an answer that matches. I know I have always thought of Col C as over 8-3/4kw but that is not correct.
 
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