cbirschbach71
Member
- Location
- Wisconsin
- Occupation
- Electrical contractor
Hey all,
I've been in the trade for 15 years and had my own business for 3. Most of my experience is residential based. I'm trying to do a service calculation for a potential customer. They are going to have 3 kilns. While I know it's not necessary legal, for comparison sake I'm calculating them as ranges. Two are 15.1 KW and one is 9.7 kw. Using note 2, I came up with a final number of 14.6 KW. Here's where I get confused.. for a feeder calculation, do I only use one entry of 14.6 KW for my calculation, or do I need 3? If I'm understanding the purpose of the table, they are assuming that all units will not often be running simultaneously and you can therefore reduce the calculated rating. Any input would be appreciated. I know they are kilns and technically can't be calculated this way, but the times they will be be on are slim to none. Thanks.
I've been in the trade for 15 years and had my own business for 3. Most of my experience is residential based. I'm trying to do a service calculation for a potential customer. They are going to have 3 kilns. While I know it's not necessary legal, for comparison sake I'm calculating them as ranges. Two are 15.1 KW and one is 9.7 kw. Using note 2, I came up with a final number of 14.6 KW. Here's where I get confused.. for a feeder calculation, do I only use one entry of 14.6 KW for my calculation, or do I need 3? If I'm understanding the purpose of the table, they are assuming that all units will not often be running simultaneously and you can therefore reduce the calculated rating. Any input would be appreciated. I know they are kilns and technically can't be calculated this way, but the times they will be be on are slim to none. Thanks.