SHORT CIRCUIT FOR XFMR 33/6.6 kv

[m sleem]

Having XFMR 30MVA, 33/6.6KV where: SC MVA Is 750.

Can we apply the following equation to obtain the SC level on the secondary side:

750*10^6=1.73*6.6*10^3* Isc

?

 

[richwaskowitz]

If you knew the transformer's impedance, the maximum theoretical available fault current could be calculated like this:

FLA per phase = 30,000,000 VA / 6600 V x 1.732 = 2624 Amps

If the unit's impedance were for example 5%, then the available fault current would be 2624 / .05 = 52,500 Amps.

 

[mivey]

Having XFMR 30MVA, 33/6.6KV where: SC MVA Is 750.

Can we apply the following equation to obtain the SC level on the secondary side:

750*10^6=1.73*6.6*10^3* Isc

?

yes

 

[m sleem]

If you knew the transformer's impedance, the maximum theoretical available fault current could be calculated like this:

FLA per phase = 30,000,000 VA / 6600 V x 1.732 = 2624 Amps

If the unit's impedance were for example 5%, then the available fault current would be 2624 / .05 = 52,500 Amps.

Many thanks..