cflava
Member
- Location
- Greensboro, NC
I am currently studying for my electrical exam and NC is still testing off the 2011 book. Anyway while studying from Mike Holt's Electrical Exam Prep book, the section on sizing the system bonding jumper for transfomers confused me with on the answers.
System Bonding Jumper Example 3:
Question: What size bonding jumper is required for a 112.50 kVA, three-phase, 480-120/208V transformer, when the secondary conductors are two parallel 3/0 AWG conductors?
Answer: 2 AWG
Cmil of 3/0 = 167,800 mil X 2 = 335,600 cmil
Table 250.66 based on 335,600 cmi = 2 AWG
My question is why would you wan to use the paralleled conductor size when the conductor is not paralleled would be sized at 400kcmil? Don't you have to size the system bonding jumper by 250.66 based on the original calculated size of the conductor despite whether or not it is run in parallel? The figure 12-61 shows the system bonding jumper to be the wire that goes from the transformer neutral (XO) to a grounding terminal block on the transformer.
System Bonding Jumper Example 3:
Question: What size bonding jumper is required for a 112.50 kVA, three-phase, 480-120/208V transformer, when the secondary conductors are two parallel 3/0 AWG conductors?
Answer: 2 AWG
Cmil of 3/0 = 167,800 mil X 2 = 335,600 cmil
Table 250.66 based on 335,600 cmi = 2 AWG
My question is why would you wan to use the paralleled conductor size when the conductor is not paralleled would be sized at 400kcmil? Don't you have to size the system bonding jumper by 250.66 based on the original calculated size of the conductor despite whether or not it is run in parallel? The figure 12-61 shows the system bonding jumper to be the wire that goes from the transformer neutral (XO) to a grounding terminal block on the transformer.