vortiz.08
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So I have 8 #250 in (2) 2 1/2” I need a wireway plus I need to splice In the wireway I’m also going from 250 aluminum to 3/0 copper just trying to understand this better
So I have 8 #250 in (2) 2 1/2” I need a wireway plus I need to splice In the wireway I’m also going from 250 aluminum to 3/0 copper just trying to understand this better
Splices only require 6X in the code rules, but in my opinion for what you are doing even 8X is not enough. What method are you using to make the splices?But I will have splices in this how do I calculate that
But I will have splices in this how do I calculate that
376.22(A) says 20 percent fill for the contained conductorsMay be wrong here but you don't need to calculate for splices. Using the multiplier (6 or 8) times the largest conduit will take this into account. Box fill is only used with conductors smaller that #4
376.22(A) says 20 percent fill for the contained conductors
376.56(A) says the conductors and splices can't fill any cross section more then 75 percent. So the splicing method will make some difference - though staggering splices so they are not all at same cross section will help with that.
Absolutely based on splice method. Crimped butt splice type devices typically won't take up as much room as Polaris connectors or similar.Good to know. So per the OP's question, how would you calculate how much fill the splices take up? Based on splice method?
Depends on the spice method, and maybe whether or not you put all spices in same cross section.If you keep your fill below 20% IMO it's nearly impossible to exceed 75% with the spices.