My Answer
My Answer
B
(2) A wall mounted box has a conduit into its left side & down from its bottom. Each contain 10 #4 wires which are spliced in the box. Minimum box size?
To calculate the box size you need to determine the size of the conduit needed to properly hold 10 #4 conductors. Given the size of the conduit. Since we have angle splice, we multiply by 6 for both length and width.
Table C.1 [70-746] is for EMT. Under type THWN-2 the #4 row, you find that the smallest conduit that will hold 8 conductor is 1? (which holds 10).
You can also do it the hard way with Chapter 9 Table 5 type THWN-2 the #4 row which gives 0.0824 in2 per wire or a total of 0.824 for all wires. The Table contains 0.814 in the 40% column for 1? EMT. Now dividing 0.814/0.824 gives 0.988. According to table note 7 under these circumstances if the division gives 0.8 or higher, the conduit is big enough.
Either way we get 1? conduit. Multiplying that by by 6 gives 9, so the box must be at least 9x9. The depth of the box must be enough for the conduit to fit in the side so the 1 inch deep box can't be used.
The smallest box is 10?12?3 from the list
Code Ref:
Table C.1 OR Chapter 9 tables 3 & 5 and note 7
314.28(A)(2)
Index:
Conduits ? Conductors, number in
Boxes (outlet device, pull, and junction) ? Junction, pull see Junction Boxes
Junction Boxes ? Size ? Conductors 4 AWG and larger