Slope in transformer differential protection

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arjun_athi

Member
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SAUDI ARABIA
Dear all,

can anyone explain me what is the exact meaning of slope in transformer differential protection and what exactly this is doing on the differential relay .

Normal setting for the slopes are slope 1 m1=0.3 and slope m2=0.6 or 1.
Awaiting for your valuable reply.
 
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skeshesh

Senior Member
Location
Los Angeles, Ca
Take a look at this application paper (and by take a look I mean read thoroughly!): http://power-sales.com/pdfs/TransformerDifferential.pdf

The material is dence so it may take a couple of reads and writing/drawing phasors but it will make sense after a while. The slope you are refering too is the slope between the differential current (Id) and restraining current (IR). Depending on the tripping characteristics you want to achieve, the graph will have several sections, each with a different "slope" that defines the how tripping occurs - the slope is calculated using the values read from your CTs. Again, if you pay attention a couple of times you will get it - I found it helpful to make sure to understand the definitions in the earlier parts of the paper, else you may be lost.
 
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