Re: speed of electrons
It?s not a bad guess, Ronald, but I?m afraid that it doesn?t account for the capacitors that have nothing but air, or even a vacuum, between the plates. Actually, the truth is simpler and easier to understand.
The parallel plates are made of metal. So there will be permanently fixed positive charges (protons) in the middle of each atom of metal, and negative charges (electrons) spinning around the outside. Some of the electrons are free to move, if they are given a push (by a voltage source). When the capacitor has no power applied, the net sum of the negatives equals the positives, so that each of the two parallel plates has a balanced charge.
Now start applying a current. Let?s talk DC first. Using a battery or other DC voltage source, start pushing electrons down the wire toward one of the two plates. The electrons cannot jump through the gap to the second plate, so they start to build up on the first plate. Now imagine yourself as being a ?free-to-move electron? on the far plate. A moment ago, everywhere you looked everything was balanced (positive equals negative). But now there is a build-up of negatives just across the gap. Remember the ?opposites attract, likes repel? rule? You have a negative charge, and you see a build up of negative charges nearby, so you will feel a force that pushes you away from the plate, and out the wire on the opposite side of the capacitor. That is how current ?passes through? a capacitor. No electron that enters one wire and goes to one plate ever makes it out of the capacitor. Rather, it pushes a different electron away from the far plate, and that other electron continues the current flow out the other wire.
The final DC-related question is, ?Why does the current stop flowing?? As the electrons on the far plate are pushed away, they leave behind (on the far plate) a net positive charge. As this process keeps going on, as more negatives build up on the near plate and more ?absences of negatives? (i.e., net positives) build up on the far plate, an electric field builds up between the plates. This field creates a voltage that is opposite in direction to the voltage source that started current flowing in the first place. Eventually, the voltage built up by the capacitor itself matches the voltage of the battery, and no more current can flow. Why not? Because of Ohm?s Law: V = I * R. But in this case, you have to include the total voltage, which equals the battery voltage minus the capacitor?s built up voltage. When the two are equal, the total voltage is zero, and therefore the current I = 0.
Last point: What?s different about AC? The AC source pushes electrons down one wire towards the capacitor on one half of the cycle, and pushes electrons down the other wire into the other side of the capacitor on the other half cycle. So long as the source voltage keeps changing (up and down, positive and negative), there will be a continuous current flow (which also keeps changing up and down, positive and negative).