Step-down Transformer

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When determining the Power after a 480V 3p Transformer, utilizing the A=VA/(1.732*V) formula. is the outcome the amount per leg/phase?

so for instance, 60A 480V-208/120 Transformer would provide about 83 A. Is this per leg/phase?
 
The answer to your question is “yes”, but I can’t make sense of your example. If 60A is the primary current, that would correspond to a 50KVA transformer and the resulting secondary current would be about 139A.

And if you already know the primary current, you can simply ratio it by the voltage ratio: 60 x (480/208) = 138.5.

Ignoring losses…..
 
A transformer doesn't change the power of an electrical system. It is the same on the primary and secondary side of the transformer. A transformer changes the voltage and current of the system (one goes up as the other goes down, based on the turns ratio).

Also ignoring losses.
 
If you could show how you got those numbers…
As mentioned above, kVA is kVA, no matter if It’s coming or going…
that 1.732 comes into play also in a delta with respects to line currents vs phase currents
you can have 60 amps of phase currents but that will equal 104 amps of line current.
 
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