- Location
- Wisconsin
- Occupation
- PE (Retired) - Power Systems
It sounds like the manual is saying that the Z of the entire fault path is 50 ohms, 40 from the impedance of the line and tower which is in series with 10 from the ground rod.
The result, before the person touches the tower is Ifault= 5000V/(40+10) = 5000/50 = 100A. This means that the voltage drop across the impedance of the line and tower is 100*40 = 4000V, and the voltage drop across the ground rod is 100*10 = 1000V.
When a person touches the tower they create a parallel path, with the 10 ohms of the ground rod. This new parallel resistor is in series with the 40 ohms of the tower and line, so the touch potential is only 1000V.
Clear as mud, but typical of the short cuts taken by a writer when they are trying to reach a specific conclusion.
The result, before the person touches the tower is Ifault= 5000V/(40+10) = 5000/50 = 100A. This means that the voltage drop across the impedance of the line and tower is 100*40 = 4000V, and the voltage drop across the ground rod is 100*10 = 1000V.
When a person touches the tower they create a parallel path, with the 10 ohms of the ground rod. This new parallel resistor is in series with the 40 ohms of the tower and line, so the touch potential is only 1000V.
Clear as mud, but typical of the short cuts taken by a writer when they are trying to reach a specific conclusion.