S slav Member Feb 1, 2009 #1 What is the minimum unit load for general illumination of 4500 sq. ft. single family dwelling when the actual number of general purpose receptacls is unknown?
What is the minimum unit load for general illumination of 4500 sq. ft. single family dwelling when the actual number of general purpose receptacls is unknown?
roger Moderator Staff member Location Fl Occupation Retired Electrician Feb 1, 2009 #2 Read article 220 and let us know what you come up with. Roger
Rockyd Senior Member Location Nevada Occupation Retired after 40 years as an electrician. Feb 1, 2009 #3 Perfect answer Roger!
S slav Member Feb 1, 2009 #4 test question test question Article 220 says 3va per sq.ft. is to cover both lighting and receptacles for dwelling unit. 4500 * 3 = 13500 I think that is right. Thanks
test question test question Article 220 says 3va per sq.ft. is to cover both lighting and receptacles for dwelling unit. 4500 * 3 = 13500 I think that is right. Thanks
roger Moderator Staff member Location Fl Occupation Retired Electrician Feb 2, 2009 #5 Correct. Roger
