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boptrop:
You ask a good question, but I think it is the wrong question, and you did not provide enough information.
We really need more load information.
Using some of your data I can roughly conclude:
1. Maximum available power to the load is 20*120 = 2400 W.
2. Don't know if you have a single wire as a load, or multiple wires physically in parallel. If multiple wires physically in parallel, then electrically these could be either series or parallel.
3. 2400 W at 480 V is 5 A. This would require a load resistance of 96 ohms or about 100 ohms. Nichrome 60 is 6.75 ohms/ft and is 0.01" in diameter. 15' of 6.75 ohms/ft is 101 ohms. Looks like your load might be a single strand 15' long.
4. Reduce your length to 2' and the voltage required is 480*2/15 = 64 V to get about the same wire temperature. Current does not change, thus, 5 A.
5. You refer to a variable transformer followed by an isolation transformer. Apparently the variable transformer is OK, but the isolation transformer failed. You mentioned SCRs. I don't know why these were needed if you had a Variac (variable transformer). Placement of the SCRs could have been the cause of transformer failure.
6. For your 2' long 60 V wire you only need a secondary current capability of 5 A or a 300 VA transformer.
7. If the transformer you have is 2.5 kVA then the 120 V winding is good for about 20 A. Run in reverse with the 120 V winding as the secondary you could draw about 20 A on this secondary and be within rating. The transformer will run cool in your application, especially using a Variac at the input for voltage and thus temperature control.
Most Variacs are wired to produce about 140 V maximum with 120 V input. Thus, you can get more than 60 V out.
8. Need to know more about why SCRs are needed.
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