mshields
Senior Member
- Location
- Boston, MA
If you have a 2500kVA transformer and say it’s has a 55/65 degree such that you get 12% more at the 65 deg rating. I believe the maximum fault current is nevertheless based on the 2500kVA value, divided by the decimal value of the impedance and then converted to amps (or switch to amps first and divide it by the decimal value of the impedance).
But a) am I correct that you would never use the 65 deg KVA rating and b) why is that so?
Thanks,
Mike
But a) am I correct that you would never use the 65 deg KVA rating and b) why is that so?
Thanks,
Mike