Trouble with voltage drop

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Van36

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Can anyone pleae help me, I'm tryin do a voltage drop calculation but I think i'm missing something in my notes about the formula. Anyway could someone tell me what my voltage drop will be on
Voltage = 123v
Amps = 20a
Lenght = 1000ft
Wire size = #8 thhn or thhw stranded
Phase = 1

There will be two branch circuits of 20a breakers 1000ft way, one of them will continue another 120ft, my voltage at the panel 123v, i will be running 2 neutrals and 1 ground. Its underground and i have a 2" pvc pipe . I would like the formulafor the drop if you could.
 
Voltage = 123v
Amps = 20a
Lenght = 1000ft
Wire size = #8 thhn or thhw stranded
Phase = 1

You can not get there using #8 cu. If you checked the calculator given in the other post, you need 2/0 if the load is really 20 amps. If you run 2 hot legs, can you put 10 amps on each leg? If so you can use #2 with 2 neutrals.
 
It will be cheaper to boost the voltage up close to 600 volts then drop it back down at the load.

Two 5 kVA transformers will cost less then the difference between 2/0 copper and the right size for the current / voltage combination you can use.
 
Can anyone pleae help me, I'm tryin do a voltage drop calculation but I think i'm missing something in my notes about the formula. Anyway could someone tell me what my voltage drop will be on
Voltage = 123v
Amps = 20a
Lenght = 1000ft
Wire size = #8 thhn or thhw stranded
Phase = 1

There will be two branch circuits of 20a breakers 1000ft way, one of them will continue another 120ft, my voltage at the panel 123v, i will be running 2 neutrals and 1 ground. Its underground and i have a 2" pvc pipe . I would like the formulafor the drop if you could.

Formulaa: 2 KID / VD or CM 2x12.9x20x1000 / #8 = 16500 cm(Tbl 8) Ans: 516,000 / 16,500 = 31.27 is the calculated Voltage Drop.
 
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