So Cal
Member
- Location
- Los Angeles, Ca
An SB 6000 has 3 strings of 11 Upsolar 225s. One upsolar panel needed replacement, its output was zero. So the system was operating essentially with two strings of 11 and one string of 10.
The strings of 11 measured 363V, while the string of 10 measured 330V. Paralled in the inverter we get 352V for the three strings combined.
The amps are 5.5 x 3 strings parallel = 16.5
3 strings of 11; 363 x 16.5 = 5,989.5 W x 5.5 x 365 = 12,023.9 yearly kWh (roughly)
2 strings of 11 = 1 string of 10; 352 x 16.5 = 5,808 x 5.5 x 365 = 11,659.9 yearly kWh
Applying percent difference equation:
= 3.1%
The difference in production according to these figures is the same % of non producing (or missing) solar modules (3%). My understanding has always been that unbalanced strings have a bigger effect than this. Which leads me to believe that there is some factor that I am not taking into account.
The strings of 11 measured 363V, while the string of 10 measured 330V. Paralled in the inverter we get 352V for the three strings combined.
The amps are 5.5 x 3 strings parallel = 16.5
3 strings of 11; 363 x 16.5 = 5,989.5 W x 5.5 x 365 = 12,023.9 yearly kWh (roughly)
2 strings of 11 = 1 string of 10; 352 x 16.5 = 5,808 x 5.5 x 365 = 11,659.9 yearly kWh
Applying percent difference equation:
(12,023.9 - 11,659.9) | ? 100% | |||
[(12,023.9 + 11,659.9)/2] |
The difference in production according to these figures is the same % of non producing (or missing) solar modules (3%). My understanding has always been that unbalanced strings have a bigger effect than this. Which leads me to believe that there is some factor that I am not taking into account.