I agree with that.For an ideal centrifugal fans, power required varies with the cube of the speed.
50/60 Hz =0.833. (0.833)^3 = 0.579.
At 50 Hz the fan power will be around 58%, call it 60% of the power at 60 Hz.
For centrifugal fans and pumps, torque varies with the square of the speed.
Since horsepower = k x torque x speed, horsepower varies with the cube of the speed.
Losses and specific fan/pump characteristics will cause some variations.
And if it is not a centrifugal fan or pump, i.e. a "Constant Torque" load, the power requirement varies directly as the speed reduction. So a 60Hz designed machine will require 83.3% of the power (HP or kW) when operated at 50Hz.
Jraef,
What do you think of this quote:
Variable Torque. Centrifugal pumps, fans,blowers, and
compressors are good examples where torque varies as the square of the
change in speed and the horsepower (work) varies as the cube of the change in
speed.
from http://www.yaskawa.com/site/dmdrive.nsf/link2/MNEN-5JFQNW/$file/AR.AFD.02.pdf