Let’s look at the situation mathematically.
Let's say you have a 120V circuit that is 500' from the load that operates normally at 5 amperes.
VD = I x R, So:
2A x 1.98-ohms (Table 8) = 3.96 volts dropped
Now, if you increase the load, see what happens to the volts dropped:
5A x 1.98-ohms (Table 8) - 9.90 volts dropped.
While this is a simplified and extreme case, it clearly shows the properties of electricity...