Thanks all for the replies.
Its a Fotek SSR-40 DA relay:
View attachment 2552885
I finally got back to remove it and brought it home,
Just set it up on the test bench (on a proper heat sink).
With a known good 24 VDC power supply its working fine.
117 Volts on the line side 116 Volts on the load, 1 V drop across the relay. Rigged it up to a space heater set a 600 Watts and its right at 5.6 Amp with my meter.
So the issue is elsewhere in the machine.
Here is an excerpt from the link below:
“The voltage drop in an SSR is usually 1 V to 1.6 V, depending on the load current. For small loads (less than 1 A), the heat produced is safely dissipated through the relay’s case. High-current loads require a heat sink to dissipate the extra heat. See Figure 6.
For example, if the load current in a circuit is 1 A and the SSR switching device has a 2 V drop, the power generated is 2 W. The 2 W of power generates heat that can be dissipated through the relay’s case.
However, if the load current in a circuit is 20 A and the SSR switching device has a 2 V drop, the power generated in the device is 40 W. The 40 W of power generates heat that requires a heat sink to safely dissipate the heat.”
The link explains the in-depth view of solid state relays and brief explanation why you have a voltage drop at the relay output.
Temperature rise is the largest problem in applications that use solid state relay (SSR). As temperature increases, the failure rate of SSRs increases.
electricala2z.com
In summary:
There is always voltage drop at the output of the relay--as a consequence of heat generated by the semiconductor.
The load is functioning OK. . . there’s nothing wrong with it.
It is important to keep the temperature tolerance of the semiconductor to prevent further loss (voltage drop). . . brought by heat build-up.. . and that is-- deploying the correct size heat sink.
This is explained on that link.
Just something to keep in mind:
Solid State Relays (as mentioned earlier) do not relay turn off when not conducting. They conduct on the principles of semiconductor “DOPING”.. . which is done by introducing positive electrons to “EXCITE” the doped semiconductor to allow electrons to flow.
Unlike copper media (wires or bars) that conduct every time you connect them to live source. . . semiconductor needs a boost in or order for them to conduct.
It is through this process that cause them to emit heat (the nemesis of semiconductors) and therefore the result of having voltage loss.
Note:
I was hoping our Brit (Bes ) friend would join the fray--and contribute some (educational) input--to keep the topic from becoming horribly convoluted.