Try 335/580. That presumes a balanced three-phase load. The phase-to-phase voltage drops by 20. The phase-to-neutral voltage is equal to the phase-to-phase divided by the square root of 3.
Try 335/580. That presumes a balanced three-phase load. The phase-to-phase voltage drops by 20. The phase-to-neutral voltage is equal to the phase-to-phase divided by the square root of 3.
Just wondering, because Chapter 9 Table 9 states values in Ohms to Neutral, which seems to imply voltage drop would be given in volts to neutral, even more so when dealing with unbalanced currents.