SparkyDave1990
New member
- Location
- Milwaukee, WI, United States
Hey guys,
First time posting so take it easy on me. My question involves the voltage drop equation. My boss put me in charge of the lighting and I don't wanna screw up the first thing he puts me in charge of.
I'm working warehouse lighting with 277v lighting on a 3 phase 480 volt panel. Each light draws about 0.5 amps and the furthest one is approximately 400' away from the panel. I'm running it in steel conduit and until it splits off it will be all 3 phases along with the neutral and ground in the same pipe.
My question is what do I use for the amperage value and voltage value for the voltage drop calculation to see if I need to upside the wire? Do I use 20a be a use that's the size breaker it's going on or the .5a for the current the fixture draws. There are 8 on each circuit. Do I use 277v or 480 because it's a single phase circuit on a 3 phase system?
First time posting so take it easy on me. My question involves the voltage drop equation. My boss put me in charge of the lighting and I don't wanna screw up the first thing he puts me in charge of.
I'm working warehouse lighting with 277v lighting on a 3 phase 480 volt panel. Each light draws about 0.5 amps and the furthest one is approximately 400' away from the panel. I'm running it in steel conduit and until it splits off it will be all 3 phases along with the neutral and ground in the same pipe.
My question is what do I use for the amperage value and voltage value for the voltage drop calculation to see if I need to upside the wire? Do I use 20a be a use that's the size breaker it's going on or the .5a for the current the fixture draws. There are 8 on each circuit. Do I use 277v or 480 because it's a single phase circuit on a 3 phase system?