voltage drop

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jcapp

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I am a new user.
I having troulbe with VD.
K=12.6 L=100ft I=45 CM=#6--26,240
I am looking at a practice question, the method is:
VD=2KLI x 0.866 / CM. What is 0.866, does it have to do with 3 Phase
 
Re: voltage drop

You already asked that question here

So this is a duplicate posting, and I am closing it.
 
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