Re: voltage drop
1.6 mm2 is a somewhat unusual size (a #15).
I think it is a safe assumption that the current is too small to raise the temperature of the wire and that AC and DC resistance are equal. Therefore, resistivity is taken to be k = 0.0185 ohms mm2/m. If the cable is 80 m long, the conductor is 160 m. (Back and forth)
==>
resistance = resistivity x length / cross sectional area
= 0.0185 x 160 / 1.6 = 1.85 ohms
The technical specifications for the coil should tell you how much current it draws and the minimum voltage it will work with. If you know this voltage and the lowest voltage of the power source, you can figure out the maximum voltage drop you can allow.
To get the voltage drop, simply take resistance times current.