I feel stupid asking this question, I have done the math over and over and come up with the same answer, so I am missing something obvious.
here is what I have
574 amp load, 3 phase, 240 volt, distance to subpanel, 350'
copper conductors, thhn, 5% vd. this is not a real situation, I am doing it for practice.
1.732x12.9x574x350 = 4488668.52 / 12 = 374,055.71 cmil so I go to table 8 which gives me 400kcmil
400 is only good for 335 amps.
what am I missing here? thanks for the help calvin
here is what I have
574 amp load, 3 phase, 240 volt, distance to subpanel, 350'
copper conductors, thhn, 5% vd. this is not a real situation, I am doing it for practice.
1.732x12.9x574x350 = 4488668.52 / 12 = 374,055.71 cmil so I go to table 8 which gives me 400kcmil
400 is only good for 335 amps.
what am I missing here? thanks for the help calvin