I'm having a brain freeze...
a water heater with (2) 6,000 watt elements, both can run at the same time...to find out the breaker size; I add both elements together (12,000 w), divided it by the voltage 208 (Single Phase)...I get 57.69 amps. But to find the breaker size I need to divid by 2(since it is 208 single phase)and I get 29 amps.....So i need to put it on a 2p-40a breaker with #8 awg..
Does this sound right.....
a water heater with (2) 6,000 watt elements, both can run at the same time...to find out the breaker size; I add both elements together (12,000 w), divided it by the voltage 208 (Single Phase)...I get 57.69 amps. But to find the breaker size I need to divid by 2(since it is 208 single phase)and I get 29 amps.....So i need to put it on a 2p-40a breaker with #8 awg..
Does this sound right.....