tallguy
Senior Member
eric stromberg said:But we love this stuff. What else would we do?![]()
Practice your Vulcan death grip??:wink:
eric stromberg said:But we love this stuff. What else would we do?![]()
steve66 said:Just last week, on the show "Are you smarter than a 5th grader", they asked the question:
"How many watts are in a kilowatt-hour?"
They said the correct answer is 1000. If that is correct, then there are also 1000 watts in a kilowatt-second, and 1000 watts in a kilowatt year.
steve66 said:The question was kind of like asking how many feet are in 1000 cubic feet. They are different things.
tallguy said:Practice your Vulcan death grip??:wink:
Wouldn't the rate of change in power be what/hours per hour, like 32 ft/sec per sec?rattus said:One "watt/hour" indicates an increase in power of one watt in one hour . . .
In other words, "watts/hour" indicates an acceleration of power
"watts/hour x hours" = watts not "watt-hours'
rattus said:In other words, "watts/hour" indicates an acceleration of power
No, it would just be watts per hour (or it can be written as watts/hour). But then, it still has no useful application.LarryFine said:Wouldn't the rate of change in power be watt/hours per hour. . . ?
bcorbin said:Just to be a jerk, :grin: it would actually be a velocity of power, if the whole (displacement, velocity, acceleration) analogy holds. "Watts/hour" would be a function of the first derivative of power. It would be the second derivative of energy; i.e., an acceleration of energy.
Sorry...I just had to take the shot. I don't get to catch Rattus being wrong (even slightly) very often.
LarryFine said:Wouldn't the rate of change in power be what/hours per hour, like 32 ft/sec per sec?
Or is that what "watts/hour x hours" means?
rattus said:No! (watts/hour) x hours yields watts.
We could say,
watts/sec =(joules/sec)/sec which is analgous to (feet/sec)/sec
Charlie is right. The expression "watts/hour" is rarely if ever used in power engineering.
bcorbin said:Just to be a jerk, :grin: it would actually be a velocity of power, if the whole (displacement, velocity, acceleration) analogy holds. "Watts/hour" would be a function of the first derivative of power. It would be the second derivative of energy; i.e., an acceleration of energy.