wire size

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If it is a continuous load you must use 125% of the load for minimum conductor size as well as overcurrent protection.

So if not a continuous load your conductor must be rated at least 38 amps - and a 40 amp overcurrent device would meet code.

If a continuous load then the conductor must be rated at least 47.5 amps and you would need a 50 amp overcurrent device.

8 AWG 75 deg conductor is needed in either case, but you could need 6 AWG if you have to use 60 deg ampacity or if any other adjustments are necessary.
 
my quetion is do I have to calculate the 125% or it is calculated by the manufactire?

my quetion is do I have to calculate the 125% or it is calculated by the manufactire?

my question is: do I have to calculate the 125% or it is calculated by the manufacture and it is included with the name plate data?
 
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my question is: do I have to calculate the 125% or it is calculated by the manufacture and it is included with the name plate data?

The nameplate rating is what it pulls.
It does not include the 125% that is HVAC and motor name plates.
 
The 125% for continuous will not be included in the nameplate current listing.
If an appliance lists a minimum circuit ampacity instead, I would expect that to take into consideration the 125%. But keep in mind that "continuous" adjustments for branches and feeders generally do not apply to motor loads.
Also for a single load on a branch breaker you may need to consider the 80% of rating rule.

Tapatalk!
 
The 125% for continuous will not be included in the nameplate current listing.
If an appliance lists a minimum circuit ampacity instead, I would expect that to take into consideration the 125%. But keep in mind that "continuous" adjustments for branches and feeders generally do not apply to motor loads.
Also for a single load on a branch breaker you may need to consider the 80% of rating rule.

Tapatalk!
Don't confuse anyone here into thinking a "double adjustment" is needed.

If we take the OP unit with a rating of 38 amps and multiply by 125% we get 47.5. That is the minimum ampacity of conductor needed. At same time if we use that same figure as a base for minimum overcurrent protection we will also meet the 80% loading rule of the device. 38 amps is less then 80% of a 50 amp breaker in this case.
 
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