Needing a real motor expert to chime in on this one. At our power plant, we have two 60 HP 480v oil pumps as part of a steam turbine oil pump skid (european manufacture). The motors are connected across the line start. Recently we had a failure of one of the motors due to a broken plastic cooling fan and subsequent overheating of the motor. We replaced it with a motor of the same manufacturer but slightly different configuration. The biggest change was that the motor connections in the peckerhead of the old motor was by terminal blocks & jumpers and the new simply had motor leads. The new motor is a 12 lead motor and we connected it in the delta (run) high voltage configuration. When the new motor was started, it repeatedly tripped the instantaneous trip breaker in the bucket. We bumped the instantaneous trip point up two settings and still it would not start. Not until after we had pulled the new motor out and sent it back to our local vendor for testing was it discovered that the old motor had been connected in the wye (start) configuration. This was the connection from the factory and we have since confirmed the other pump is the same way. I have never seen a 12 lead wye start delta run motor left to run continously in the wye connection. I understand this will not allow the motor to deliver the same torque but it is currently running fine (and starting beautifully!) and driving the pump as it needs to. Current readings are approx. 42 amps and nameplate is 69. The load is constant and does not vary. Is there anything detrimental to leaving it in this configuration? Is the motor essentially "derated" but since it is driving the load properly and is well under nameplate current all is well? Thanks in advance.
If I can take a guess the motor that failed was probably an older motor prior to the high efficiency motors of today. The inrush required to start the original motor was much lower than the replacement. Check this out. Keep in mind that the purpose of the MCP is to protect the motor circuit should the motor experience a winding failure. The intent is to take the motor off line should there be a winding to ground winding failure and before it could escalate into a phase to phase winding failure. You want to set the MCP such that the magnetic pickup is just above the inrush required to start the motor. It is interesting to note that you did state that you "bumped" the magnetic pick up setting up 2 but then neglected to state what that setting was. You will note that for a design B energy efficient motor you are allowed to set the MCP up to 17 times the FLA of the motor which should be 69 x 17=1173a. It is interesting that you included a great deal of information but did not state what the MCP size was and where you had set it which makes a bit difficult to address your question. Is the MCP 150a? If so it should have a mag setting of up to 1500a . A C-H HMCP has setting has setting A-H, A=450 and H=1500. You would select E=1050a If you had a 100a MCP you would set ti at the highest setting available.
Please refer to NEC art 430-52(C)(3)
Exception No. 1: Where the setting specified in Table
430.52 is not suff?cient for the starting current of the motor,
the setting of an instantaneous trip circuit breaker shall be
permitted to be increased but shall in no case exceed
1300 percent of the motor full-load current for other than
Design B energy eff?cient motors and no more than
1700 percent of full-load motor current for Design B energy
eff?cient motors. Trip settings above 800 percent for
other than Design B energy eff?cient motors and above
1100 percent for Design B energy eff?cient motors shall be
permitted where the need has been demonstrated by engineering
evaluation. In such cases, it shall not be necessary
to first apply an instantaneous-trip circuit breaker at
800 percent or 1100 percent.