If temp rating of a transformer changes, its efficiency may also change. So if one knows efficiency, power factor etc of a transformer per OP and post #4, it is possible to calculate the heat rejection of the transformer using the following identity:
{(1-output/input)*[output/(output/input)]}=input-output...................(1)
Here input-output= losses of transformer=Heat rejection by transformer under steady state,
output/input=Efficiency of transformer,
output=KVA*Powerfactor.
Substituting values from post#4,
Output=112.5*0.9=101,25KW
Output/Input=0.95 on the left hand side of (1), the heat rejection is
(1-0.95)*(101.25/0.95)=5.33kJ/s or approximately 5 kW.
{(1-output/input)*[output/(output/input)]}=input-output...................(1)
Here input-output= losses of transformer=Heat rejection by transformer under steady state,
output/input=Efficiency of transformer,
output=KVA*Powerfactor.
Substituting values from post#4,
Output=112.5*0.9=101,25KW
Output/Input=0.95 on the left hand side of (1), the heat rejection is
(1-0.95)*(101.25/0.95)=5.33kJ/s or approximately 5 kW.