We have buried the dead z(t) horse or at least embalmed him. Now for something important:
Let?s derive the formula for inductive reactance.
Lenz?s Law states that the emf induced in an inductor by a changing current is given by,
1) e = - L*di/dt, where the minus sign indicates an opposition to a change in current. Now let,
2) i = Im*sin(wt) then,
3) di/dt = Im*[-cos(wt)*w], now substituting eqn. 3 into eqn. 1
4) e = wL*Im*[cos(wt)] Then at t = 0,
5) e = Em = wL*Im, and
6) Xl = Em/Im = wL = Vrms/Irms
Inspection of eqns. 2 & 4 shows that v leads i by 90 degrees, but that angle is not carried by Xl; neither is Xl preceded by the operator ?j?. It is a real number with the units of ohms.
One might be tempted to take the ratio of e to i, but since these sinusoids are displaced by 90 degrees, the ratio would range between +/- infinity?useless!.
Note also, that inductive reactance only has meaning when used with sinusoidal waveforms.
Let?s derive the formula for inductive reactance.
Lenz?s Law states that the emf induced in an inductor by a changing current is given by,
1) e = - L*di/dt, where the minus sign indicates an opposition to a change in current. Now let,
2) i = Im*sin(wt) then,
3) di/dt = Im*[-cos(wt)*w], now substituting eqn. 3 into eqn. 1
4) e = wL*Im*[cos(wt)] Then at t = 0,
5) e = Em = wL*Im, and
6) Xl = Em/Im = wL = Vrms/Irms
Inspection of eqns. 2 & 4 shows that v leads i by 90 degrees, but that angle is not carried by Xl; neither is Xl preceded by the operator ?j?. It is a real number with the units of ohms.
One might be tempted to take the ratio of e to i, but since these sinusoids are displaced by 90 degrees, the ratio would range between +/- infinity?useless!.
Note also, that inductive reactance only has meaning when used with sinusoidal waveforms.