A related INDIRECT advantage to a VFD and "fully" loaded" open delta
A related INDIRECT advantage to a VFD and "fully" loaded" open delta
A reported issue in the thread from which this was forked was phase imbalance with a full loaded open delta. In the case discussed, and to an extent in a VFD controlled (with controlled acceleration) motor, the imbalance will occur on the input to the rectifier of the VFD. This would (to a level unknown to me) result in a slightly lower capacitor voltage, but as Besoeker points out, with V/f characteristics, output voltage (to the motor) will be substantially lower than nominal during acceleration.
If at nominal speed after starting, with "line" voltage from the VFD, loading to well-over-specification slip will result in high currents; the curve by Besoeker suggests (yeah, I know different motors differ, but not LOTS) that if loaded all the way to 75% PU speed, I still have "rated" torque available, but if across the line, at 6 times FLA. The thread was discussing centrifugal pumps (probably multi-stage?) which might not follow the cubic power relationship, but almost certainly not a linear relationship ... so starting POWER requirements would be lower than running, and power required during the acceleration period would increase as speed increased.
Thus the use of a VFD would logically not only reduce starting (and maximum) transformer load, but also "eliminate" phase voltage imbalance, motor phase voltage being generated by the IGBT devices in the VFD.
Also as Besoeker points out, the torque required to stall a motor is, with most traditional 3 phase induction motors, significantly above FLA. I would expect that rather than stall (300+% FLA?), it would be "protected" by the VFD.
Manual wye-delta ... not the question ... it was stalling in operation, not in (beware my perhaps rudeness) improper starting of a different motor than is even being discussed.