THE PHYSICS OF... POWER

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FionaZuppa

Senior Member
Location
AZ
Occupation
Part Time Electrician (semi retired, old) - EE retired.
Suggest googling "equivalent circuit of a induction motor" to see the missing term that makes torque by increasing the IN PHASE current. Much more to it than simple STATOR R in your Z.

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for the viewing & educational benefits for those who want to look deeper
 

Carultch

Senior Member
Location
Massachusetts
a capacitive motor ?? or the labels were switched?

attachment.php

My mistake. I intended to subtract the phase offset when making the current graph, rather than add it. You will still get the same power curve, just with a different position in time, if you made this for an inductive motor.
 

FionaZuppa

Senior Member
Location
AZ
Occupation
Part Time Electrician (semi retired, old) - EE retired.
Suggest googling "equivalent circuit of a induction motor" to see the missing term that makes torque by increasing the IN PHASE current. Much more to it than simple STATOR R in your Z.

Sent from my SM-G900V using Tapatalk

were you looking for the R term related to slip
Image(42)_thumb.png


Induction%20Motor%20Equivalent%20Circuit%20-%20Simplified_thumb.png
 

Besoeker

Senior Member
Location
UK
Assuming the motor, generator, and engine are perfect machines (meaning zero-losses) the generator providing 1kW @ 0.8pf to the motor, must also be rated 1kW @ 0.9pf, which equals 1.25kVA! However, the engine driving the generator must be rated 1kW, corresponding to 0.746Hp!

Phil
I give up..........
 

mike_kilroy

Senior Member
Location
United States
Fiona,

Right model, wrong Zeq! Zeq = Z1+Zo || [(R'2/s) +jX'2].

Phil

May help also to just write down the bottom line: that triangle again: current into the motor, I, is simply the vector sum of Isq+Isd

WHERE:


  • I is what a clamp on ammeter will read
  • Isq is the in phase torque producing current (developed due to that slip term that was so MIA until now)
  • Isd is the 90 degree out of phase current making the magnetic field, what is the A term referred a lot here as KVARs, this is constant and does not change (simplified comment - you do not need to get into the slight changes due to interactions to other things in the complex model; for these discusions you can say it is totally constant and never changes)
 

mike_kilroy

Senior Member
Location
United States
Why? His "Req" represents Thevenin equivalent impedance?

Why would you write such a thing? Are you not an engineer?

Quite simple really: r2/s is NOT equal to Zo||(r2/s)

VERY VERY VERY DIFFERENT VALUES! If you had a clue what these two terms actual values loaded and unloaded were you would not have questioned the correction. Please look it up so you learn the major difference in values.
 

Ingenieur

Senior Member
Location
Earth
Wrong. Consider physics behind operation of an eletromechanical relay or an electromagnet: magnetic energy i.e reactive energy is converted to active power here.

the reactive energy is not 'converted'
the real power moves the armature
think of it as a simple linear motor
 
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Sahib

Senior Member
Location
India
the reactive energy is not 'converted'
the real power moves the armature
think of it as a simple linear motor

The real power moving armature is derived from magnetic field energy which ,before movement ,is purely reactive energy.
 

Ingenieur

Senior Member
Location
Earth
The real power moving armature is derived from magnetic field energy which ,before movement ,is purely reactive energy.

the power is complex
you have P and Q components
before and after it moves
you don't have all Q before it moves, then all P after
the Q is constant like a motor and the P increases with movement, but the Q does not disappear or get 'converted'

like a transformer or motor you have a var inrush and then real power to operate or generate torque

if it required var a DC relay would not operate
if it were var the meter would not spin with a rack of relays connected
 
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