sparks27
Member
- Location
- Portland, Oregon
I am studying mike holt electricians math, I came across this question and cant find how the resistance for two #14 conductors comes out to 12.90 ohms
The question is stated: whats the maximum distance that two #14 can be run if they carry 16A and the allowable voltage drop is 10V?
I checked chapter 9 Tbl. 8 but cant find how he arrived at this number Help...
Dist= (4110 x 10V) / (2 x 12.90 ohms x 16A)
A=50ft
B=75ft
C=100ft
D=150ft
Thanks, Sparks
The question is stated: whats the maximum distance that two #14 can be run if they carry 16A and the allowable voltage drop is 10V?
I checked chapter 9 Tbl. 8 but cant find how he arrived at this number Help...
Dist= (4110 x 10V) / (2 x 12.90 ohms x 16A)
A=50ft
B=75ft
C=100ft
D=150ft
Thanks, Sparks