12 kw load on buck & boost

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You are welcome to do that, but a Kirchoff's Laws analysis will lead you to that result. Just ignore the magnetizing current and calculate with the current in each winding section inversely proportional to the turn count for that section.

Id rather just clamp it and see for myself and leave kirchoff for those who do not do for themselves.

Jap>
 
Did I misread this?

"If a grill rated at 12kw at 208v is supplied by a 240v system thru a buck & boost transformer will the 240v load be 50 amps ? "

I believe the supply system is 240v, and corrected to the heater's 208v rating by the transformer.
 
I believe the supply system is 240v, and corrected to the heater's 208v rating by the transformer.

:thumbsup:

What was said was that without the buck transformer the heater element would have been overloaded and the power coming from the 240V source would have been more than 12kW.
 
Yes, 16kw as I posted earlier. The same way a 240v-rated resistive load runs at almost exactly 75% (3/4) of its power on 208v, a 208v-rated resistive load runs at the reciprocal of 75%, which is 133% (4/3) of its rated power.
 
Nothing wrong with math or circuit analysis. I “do” and “can do” as many others here are capable of also.:cool:



Um, it’s a law because it has already been proved.:)
Maybe poor choice of words, it is a way of proving kirchoff law to someone that is learning about it.

That's for 12kW. But if it is a resistive heating element rated at 12kW 208V, won't it be more at 240V?
Again maybe poor choice of words. The true load is connected to 208 volts, the load the 240 volt portion of the circuit sees is still 12kW and current in that portion of the circuit has to be 50 amps to keep same kW.
 
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