Call your phases A, B, C with C being the 'high leg'.
If you supply all of the tenants from the single phase base (A,B,N), your calculated load is 904A. This lets DPW separately meter every tenant.
Now the question is what to do with 'MSB'. I calculated that MSB has a total of 188A of 240V single phase loading.
I propose that MSB be the only three phase service, but with only single phase loads. You would connect these loads 240V A-C and B-C only, with _no_ A-B loading. Any 240V load simply gets connected, any 120V circuits would be fed via a transformer.
I like your idea of putting the MSB single phase loads across just A-C and B-C. These load currents I
A-C ≈ I
B-C would each be 60° from the 904A on A-C. Because each of these load currents will be substantially less than I
A-B = 904A, their component in quadrature (at 90°) to I
A-B will end up phase shifting the total line currents on A and B a small amount, but add little to its magnitude. The components of the load currents I
A-C and I
B-C that are in-phase with I
A-B will each be down by a factor of sin(30°) = 1/2. And if these two in-phase current components are equal, they will flow through one load across to the other without impacting the current on C. And so their current component in-phase with I
A-B = 904A will be the same as if these two loads were in connected in series across the 240V on A-B, and not connected to high leg phase C. So, for example, if I
A-C = I
B-C = 100A, then they would contribute a total of 50A to the I
A-B current. The current on phase C would be 2 x cos(30°) x 100A = 173A.
I think the elevator current might still need to be 3-phase, but the OP would need to confirm this.
Your point about the supply voltage being 240A vs. 208V for loads MSB suggests that these loads should be reviewed to make sure they are compatible voltage-wise.