I don’t get your SSBJ TOTAL at 14 conductors which should run from the separately derived source enclosure to the first point of disconnect enclosure or bus
If you you are paralleling every ungrounded conductor and SSBJ into one massive conduit ok
However if you have 3 conduits equally separating pairs of ungrounded and grounded conductors in 3 conduits from source to first disconnect then you could not get the required even number of SSBJ in 3 conduits. 14 SSBJ / 3 = 4.66 SSBJ conductors in each of the conduits (not possible)
Also if you don’t have neutral loads you may be able to go with an ungrounded system and not run a neutral (which I think you call 14 SSBJ?) from XO to the first disconnect. Instead you leave xo without anything terminating to it. The SSBJs would not connect at the xo neutral but to the source cabinet ground to first point of disconnect
Here’s the math I got for your project
Primary 125.15 I = 1 AWG @75 deg c
Secondary 3608.54 I = 14 of 250 kcmil conductor parallel x 255i = 3570i
(What the heck are you powering for this many amps a small town or meth lab lol?)
SSBJ 14,500,00 x .125 = 1,812,500 mil
1,812,500 mil / 14 conductors = 129,464.286 mil individual SSBJ X 14 or 2/0 at 133,100 cm each x 14 (would only work in a single conduit as 14 SSBJ can not divide evenly into 3 conduit runs)