Great question.I think each element would draw 16.3 amps but I am not clear on how the currents would divide at common point. Would L2 carry 32.6 amps or would it divide because of the vector differences.
What's the answer (is it 28.23?), and can you show how to get it? Thanks.100313-0732 EST
avrepair:
In theory yes for 16.25, but maybe about about 10 to 20% less because of the temperature coefficient of resistance change.
Yes you need to use vector arithmetic.
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Look up Ohm's Law.
avrepair, assuming you are still addressing your water heater project, don't forget 422.13 requires that load to be treated as continuous so the 28.145 becomes a calculated load of 35.18 preventing you from using your #10 with the 30 amp required {240.4(D)} breaker.
To remember 1732 associate it with the birth year of George Washington.