BatmanisWatching1987
Senior Member
- Location
- NJ
- Occupation
- Jr. EE
Where is the rest of the work?View attachment 22427 View attachment 22428 View attachment 22429
With Problem 111
I solved it by using the following formula
S = √3∠-30*VL*IL* = √3∠-30 * (12.5∠0kV) * (70∠20) = 1515.54∠-10.
But in the other problem posted, why isn't there a 30 Degree Phase shift as well.
They are both 3 Phase Balanced Delta Loads.
View attachment 22427 View attachment 22428 View attachment 22429
With Problem 111
I solved it by using the following formula
S = √3∠-30*VL*IL* = √3∠-30 * (12.5∠0kV) * (70∠20) = 1515.54∠-10.
But in the other problem posted, why isn't there a 30 Degree Phase shift as well.
They are both 3 Phase Balanced Delta Loads.
View attachment 22427 View attachment 22428 View attachment 22429
With Problem 111
I solved it by using the following formula
S = √3∠-30*VL*IL* = √3∠-30 * (12.5∠0kV) * (70∠20) = 1515.54∠-10.
But in the other problem posted, why isn't there a 30 Degree Phase shift as well.
They are both 3 Phase Balanced Delta Loads.