In imperial units...
1,000A
2,000kcmil copper conductor
0.00284402in/sec
Actually a mixture of units.
The Ampere an SI unit.
There is no Imperial equivalent.
In imperial units...
1,000A
2,000kcmil copper conductor
0.00284402in/sec
I didn't claim to know.Then how would you know heavier ions may have a lower drift velocity than lighter electrons?
Smart $:Didn't check his numbers, but I assume his calculation is based on one electric charge per atom and atom size. The result is the average net flow rate. Additionally we're talking about copper. Proton drift is negligible, right?
When the current is by flow of ions, the current may be lesser than when the current is by electrons for the same voltage. I am trying to make that point.
Bes' is correct. When we discuss electrical circuit current (movement of electrical charges), a discussion of ion flow is superfluous and irrelevant. Extremely simplified, ion flow represents voltage change, not net circuit current flow. Consider the ion flow when a current passed through an aqueous ion solution that has net zero effect on the solution (i.e. the solution is charged and discharged concurrently, meaning there is another current source)...Then how would you know heavier ions may have a lower drift velocity than lighter electrons?My calculation is simply for current. No other extraneous factors are involved. Your comment about the voltage is thus irrelevant.
Protons do not flow in semiconductors, either. Holes do, but they aren't protons, they are electron vacancies. The only case I can think of at the moment where you will encounter naked protons in non-plasma matter is in aqueous acid solutions. Maybe on the surface of a platinum catalyst.And he wasn't talking about semiconductors either so the broader comparison sticks.
Current is charge flow. A particle with a bigger charge could move slower for the same current but as GoldDigger pointed out, it is a mobility issue. I will grant you that a huge mass takes more energy to move.Yes, but think this way: the ions initiate the current flow and not the electrons in this case. If the electric conduction is all by electrons, current flow would be faster, higher current, higher rate of charging and so shorter charging period.
Forgot again? Did not forget it in the first place. Your refusal to learn is astounding at times. Remember this?:You are forgetting Einstein again: when the speed of a particle with a rest mass approaches the speed of light, its mass tends to infinity. The conductor would simply break off the circuit due to huge weight gain if its surface electrons try to behave that way.
Suit yourself.
Understanding quantities is key. For example, we all know your relative mass increases with velocity: that is the principle. Without the quantity, you may not realize it is not significant until you get really fast.
How fast? Moving from zero to 95 million mph gives a relative mass increase of about 1%. So now you think the principle is millions of mph faster is relatively a small impact.
But not so fast, pardon the pun. When your velocity makes your relativistic mass 1 million times your rest mass, an increase of 1 foot per hour in velocity increases your relativistic mass 52%.
I already have but that teaches you little. I have a suspicion you learn better when the information comes from within.
There you go. Since current is charge flow we need only compare the particle charge to get the particle movement for the same current. I seem to recall protons and electrons have the same charge magnitude.Didn't check his numbers, but I assume his calculation is based on one electric charge per atom and atom size. The result is the average net flow rate.
I would have to search more but "proton conductor" reveals some info.Protons do not flow in semiconductors, either. Holes do, but they aren't protons, they are electron vacancies. The only case I can think of at the moment where you will encounter naked protons in non-plasma matter is in aqueous acid solutions. Maybe on the surface of a platinum catalyst.
How refreshing to hear sound logic. Good to hear from you this morning. Have fun at the dance.My calculation is simply for current. No other extraneous factors are involved. Your comment about the voltage is thus irrelevant.
Thank you kindly!How refreshing to hear sound logic. Good to hear from you this morning. Have fun at the dance.
But don't you agree heavier ions have lower mobility i.e lower drift velocity than lighter electrons for the same voltage?Current is charge flow. A particle with a bigger charge could move slower for the same current but as GoldDigger pointed out, it is a mobility issue.
You need be specific about the surface electron initial velocity. Give a value for it. Simply stating that its velocity is near light velocity could mean any value for its rest mass: it could be equal to that of an adult elephant given its velocity is assumed sufficiently near that of light.It seems you learned nothing about the value of quantities. Near light speed does not mean AT light speed. At 500 million mph (0.7456c) you have only gained 50% of your rest mass.
Here is another chance for you to learn something about quantity vs. principle starting at some near light speeds:
0.100c, 67.1 Mmph, 0.5% increase over rest mass
0.200c, 134.1 Mmph, 2.1% increase over rest mass
0.300c, 201.2 Mmph, 4.8% increase over rest mass
0.400c, 268.2 Mmph, 9.1% increase over rest mass
0.500c, 335.3 Mmph, 15.5% increase over rest mass
0.600c, 402.4 Mmph, 25.0% increase over rest mass
0.700c, 469.4 Mmph, 40.0% increase over rest mass
0.800c, 536.5 Mmph, 66.7% increase over rest mass
0.900c, 603.6 Mmph, 129.4% increase over rest mass
0.950c, 637.1 Mmph, 220.3% increase over rest mass
0.960c, 643.8 Mmph, 257.1% increase over rest mass
0.970c, 650.5 Mmph, 311.3% increase over rest mass
0.980c, 657.2 Mmph, 402.5% increase over rest mass
0.990c, 663.9 Mmph, 608.9% increase over rest mass
0.999c, 669.9 Mmph, 2136.6% increase over rest mass
I didn't claim to know.
So again, an irrelevance.
CorrigendumYou need be specific about the surface electron initial velocity. Give a value for it. Simply stating that its velocity is near light velocity could mean any value for its rest mass: it could be equal to that of an adult elephant given its velocity is assumed sufficiently near that of light.
I appreciate your appreciation.Marvelous.
I appreciate your appreciation.
I agree.Again standalone statement!
While you are correct in there is no Imperial equivalent, I consider Ampere as a universal unit. Ampere was never an Imperial unit. It is included in SI units, but SI by name has only existed since 1960, and Ampere existed well before that. Prior to 1960, SI was known as the CGS system (c.1874).Actually a mixture of units.
The Ampere an SI unit.
There is no Imperial equivalent.
The sizes of the coherent CGS units in the fields of electricity and magnetism, proved to be inconvenient so, in the 1880s, the BAAS and the International Electrical Congress, predecessor of the International Electrotechnical Commission (IEC), approved a mutually coherent set of practical units. Among them were the ohm for electrical resistance, the volt for electromotive force, and the ampere for electric current.
Indeed it did. As did most electrical units for which there is no Imperial equivalent.While you are correct in there is no Imperial equivalent, I consider Ampere as a universal unit. Ampere was never an Imperial unit. It is included in SI units, but SI by name has only existed since 1960, and Ampere existed well before that.
Then MKS.Prior to 1960, SI was known as the CGS system (c.1874).
don't forget it is reversed on the other half cycle.the current flows from the hot wire and then returns back via neutral wire. this way current completes its path.
No. The neutral only returns the unbalance. The return duty is shared by all three phases at different times. For instance, when one phase of a balanced system has the maximum current out, the other two share the return current (one phase is positive and the other two are negative.when we have a balanced 3Ph system( STAR or WYE), each phase draws the same amount of current and the neutral current provides the return path.
The returns don't all happen at the same time for each phase so they rotate the duty in cycling portions. It becomes clearer when you look at the graph of all three together.How is the return path provided incase of DELTA system?there are only 3 phases.so how is return path provided if we have a 3ph load for delta system.
All those quotes you attributed to me were from the OP, not me. I should have replied with quote to the OP rather than cut and paste; my bad.don't forget it is reversed on the other half cycle.
No. The neutral only returns the unbalance. The return duty is shared by all three phases at different times. For instance, when one phase of a balanced system has the maximum current out, the other two share the return current (one phase is positive and the other two are negative.
The returns don't all happen at the same time for each phase so they rotate the duty in cycling portions. It becomes clearer when you look at the graph of all three together.