- Location
- Wisconsin
- Occupation
- PE (Retired) - Power Systems
But it isn't.
It's I=W/(V*sqrt(3)*cosφ))
You can't ignore cosφ and get the right answer.
On a lightly loaded motor, the power factor could be 0.5 or worse in which case the current would be double what you would by ignoring pf.
You are correct about the actual formula requiring Power Factor.
However because this is a multiple choice test, and PF was not provided, nor could it be deduced, it cannot be used in determining the answer. If you are going to assume a value, other than 1.0, you might as well just randomly choose any of the provided answers and get on with the rest of the test.