mivey
Senior Member
The source is indeed on the bottom. No need to move the CT's. If it gets reversed wired, you could just swap the red and black voltage leads; probably the easiest point would be at the test block on the left side (don't have a good view of that area to see if they actually land there).So if I connect to the top and they connect to the bottom then they can just switch leads if it is wired incorrectly? I thought they were saying that the CT's would have to be removed and turned around.
In the normal mode, the CT on the left and the voltage have complimentary fluxes. The current on the right is moving in the opposite direction but the meter is wired for a reversal so that the magnetic flux is additive with the current on the left. Look at the orange and green currents and the black to red voltage. Let's look at normal and reverse wiring:
Normal: When we have a voltage rise from neutral to red (V_L-N), we also have a voltage rise from black to red (V_L-L, right to left terminal: our voltage reference). Current flows from orange to white (top to bottom) and from white to green (bottom to top). The orange current and the voltage have the same sign. The green current has the opposite sign from the voltage but the meter reverses the current so the green flux is additive with the orange flux. Now the currents and voltages have the same sign so the POCO is delivering energy to the customer.
Now reverse the source and load: When we have a voltage rise from neutral to red, we also have a voltage rise from black to red (right to left: our voltage reference). Current flows from white to orange (bottom to top) and from green to white (top to bottom). The orange current and the voltage have the opposite sign. The green current has the same sign as the voltage but the meter reverses the current so the green flux is additive with the orange flux. Now the currents and voltages are different in sign and the meter shows the customer is delivering energy but the customer is actually taking energy. Reversing the red and black voltage leads corrects the error.
Note that the CT current is weighted by 1/2 since we are using L-L voltages instead of L-N voltages.