Ok. Fine I'm too tired to make sense even to myselfinfinity said:That confused me as well. Column C is labeled not over 12KW which would fit the range in my question.
Ok. Fine I'm too tired to make sense even to myselfinfinity said:That confused me as well. Column C is labeled not over 12KW which would fit the range in my question.
Bill W said:I don't think so. I read it as add 5% to the 80% for each kw over 8 3/4, perhaps I should have chosen 90% rather than 85%, but I still calculate at least 35.4 or greater. I'm often wrong, especially when I'm sure I'm right.
To Celtic: in the notes...
Bill W said:Ok. Fine I'm too tired to make sense even to myself
infinity said:One range not over 12KW would have a maximum demand of 8KW.
Right...just figured that out, finally... so 8000/240=33.3. yeah, yeah, yeah...50/.80=40A permissible load. Now what about that 50% stuff on cord and plug fixed equipment you mentioned earlier, I'm sure there is a difference between equipment and appliances...right?infinity said:According to the parenthetic note in the table heading (Column C to be used in all cases except as otherwise permitted in note 3),I would simply use Column C for a range or ranges(s) not over 12 KW.
One range not over 12KW would have a maximum demand of 8KW.
Bill W said:Now what about that 50% stuff on cord and plug fixed equipment you mentioned earlier, I'm sure there is a difference between equipment and appliances...right?
I never mentioned 210.23 in regards to the range.david said:I am not sure how 210.23 (A) ?(D) is applicable to what you guys are discussing unless the range you are discussing is on a multi-outlet circuit.
(C) 40- and 50-Ampere Branch Circuits. Is applied most commonly to a range circuit when the cook top and oven are separate appliances feed from the same branch circuit. A lot of kitchens have a built in range and a cook top wired to a common junction box making the circuit multi- outlet.
celtic said:I never mentioned 210.23 in regards to the range.
The post got a bit sidetracked...we originally started talking about a 20A circuit with an 18A load, then went onto ranges.
It's all infinity's fault![]()
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infinity said:Thanks Celtic.....
FrancisDoody said:Here is another one I see occasionally; Electric hot water heater with 4500 watt elements. Hooked up using 12/2 MC with 20 amp OCPD. (4500/240=18.75A). This installation is hard wired, on an individaul circuit so 210.23 (a) or (b) should not effect it
Bill W said:Not sure but my quick response is 220.55. Not over 12kw use column C=80% increasing 5% for each kw over 8 3/4. So, 10kw/240=41.67/.85=35.4
infinity said:A hot water heater is considered by the NEC to be a continuous load. 18.75(125%)=22.5 amps. You need a 30 amp circuit. Look at 210.20(A) and 422.13.
I chose to ignore most of the other words and here's what I found....DGrant041 said:What's short and green, but draws continuous?
(You can ignore the "short & green" part if you don't think it's funny)