djcrzysounds@yahoo.com
Member
- Location
- Scranton, Pa
Just checking... 800 Amp 3 Phase 120/208 Volt Service. Incoming conductors to be 4 parallel 4/0 feeds (4 wires each phase).
I was trying to get away with only 2 conduit runs. Sorry for not explaining... Also is it possible to run 2 sets of Service conductors in the same conduit.(As seen in a separate thread in NEC Section)
As long as you adjust the conductors ampacity per table 310.15(B)(2)(a)
Roger
Please check my math. Using XHHW-2 Copper Conductors.
4/0 @ 260Amps
x2(sets of conductors per Conduit) 520 Amps
/1.25 (For derating) = 416 Amps
x2 (For 2 sets Conduit) = 832Amps
Thanks Guys... when it doubt.. just post it..lol... now comes the fun part... how do I get 8 wires through a weatherhead? The only ones I can find have holes for 7 conductors.
Maybe you can re-calculate your neutral load and use a single neutral conductor.how do I get 8 wires through a weatherhead? The only ones I can find have holes for 7 conductors.
Maybe you can re-calculate your neutral load and use a single neutral conductor.
The grounded conductor only has to be as large as required by the load calculations and 220.61.I thought even with 120/208V 3-phase you could not derate the neutral. So if for an 800amp service you would need one or more conductors that had an ampacity of 800Amps or more.
The grounded conductor only has to be as large as required by the load calculations and 220.61.
if I might addThe grounded conductor only has to be as large as required by the load calculations and 220.61.
No different than adding any loads to an existing service or feeder...you have to do a new load calculation.I'm curious, if you used that method could you ever add any single phase 120 volt loads to the service in the future?
Thanks for adding that point, Gus. In some cases, those with small neutral loads, that section will require a larger grounded conductor than does the load calculation.if I might add
with the requirements of 250.24(C)
Thanks for adding that point, Gus. In some cases, those with small neutral loads, that section will require a larger grounded conductor than does the load calculation.