Because the heating element draws more current than the compressor? (just guessing)Then why would there be a higher MCA for the one with the heater? ...
Because the heating element draws more current than the compressor? (just guessing)
None of these calculations are valid because they've used the 60 Hz run current. When you run a motor on 50 Hz, it will turn 5/6 as fast and consume considerably less power. The compressor motor will consume about 5/6 as much power -- the refrigerant pressure ratio and the torque required to turn the compressor will be about the same at any speed. The fan motor will consume a little more than half as much power -- fan power is a cube function of speed.
A transformer will also need to be derated. The current required to saturate the core -- and its kVA capacity -- will be less at 50 Hz.
Best to send the air conditioner back to North America and use one designed for the local market.
Don't believe everything you read on the Internet....The op claims "I have input 220V 60Hz."
Because the heating element draws more current than the compressor? (just guessing)
None of these calculations are valid because they've used the 60 Hz run current. When you run a motor on 50 Hz, it will turn 5/6 as fast and consume considerably less power. The compressor motor will consume about 5/6 as much power -- the refrigerant pressure ratio and the torque required to turn the compressor will be about the same at any speed. The fan motor will consume a little more than half as much power -- fan power is a cube function of speed.
A transformer will also need to be derated. The current required to saturate the core -- and its kVA capacity -- will be less at 50 Hz.
Best to send the air conditioner back to North America and use one designed for the local market.
But, as drcampbell has pointed out the values for the comp will be different at 50Hz.the nameplate lists the FLA
comp 12.2
Heater 13.2
the fan is the same for both at 3.4
But, as drcampbell has pointed out the values for the comp will be different at 50Hz.
Easier calc is P=Twyep, it should go down, making the heater still the largest load
he states ~T is constant
and T = 5252/rpm x P
so if rpm decreases, P must decrease inversely proportional to keep T constant
Easier calc is P=Tw
SI, not Imperial.that is P = Tw
or T = P/w in Imp units
SI, not Imperial.
w is omega.
It's radians per second which is not an Imperial unit.T = P/w is valid regardless of units (as long as consistent)
I was pointing out the 5252 factor is working in Imp units (rpm, HP)
w = 2 Pi n, n = rev/sec
It's radians per second which is not an Imperial unit.
Now, please can we get back on topic and look at the OP's question?
He's got the wrong voltage and frequency for the kit he wants to power.
What do you suggest he does?
It's the SI unit for angular velocity.rad/sec is universal
It's the SI unit for angular velocity.
My reading of the situation is that the OP has an unsuitable unit for his application.
Wrong voltage, wrong frequency.
We don't seem to have information about how he came to have this piece of kit. Of course there are solutions that could make it work at nameplate ratings. But probably simpler and cheaper to get an aircon unit designed for his supply voltage and frequency.
And in most of the rest of the world but I'm not sure what point you are trying to make.aren't motors in the UK (and Europe) rated in rpm and kW?
But you still have the frequency disparity.if the cost of exchange > cost of transformer, hook her up and run
I think, that for this application, we are a bit beyond what wall warts can achieve.I wonder if there is a wall wart that will do this? (euro to US convertor)
And in most of the rest of the world but I'm not sure what point you are trying to make.
No problem.
But you still have the frequency disparity.
I think, that for this application, we are a bit beyond what wall warts can achieve.
Don't believe everything you read on the Internet.
I am using this device in Saudi Arabia not Egypt
what is the standard frequency? 50 or 60 Hz?
it's 60 Hz
127/220 or 230/400 vac?