Re: bedroom circuits
I think that this is not a violation of 210.11(B). Here is how I see it:
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- <font size="2" face="Verdana, Helvetica, sans-serif">Your total load for this set of general purpose loads is 3000 x 3 = 9000 VA</font>
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- <font size="2" face="Verdana, Helvetica, sans-serif">You supply a 600 square foot bedroom with one circuit. That is worth 3 x 600 = 1800 VA.</font>
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- <font size="2" face="Verdana, Helvetica, sans-serif">That leaves 9 circuits to supply the remaining 7,200 VA, giving each an average of 800 VA.</font>
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- <font size="2" face="Verdana, Helvetica, sans-serif">The total load on Phase A (presuming it is the one with the big bedroom) is 1800 + 4 x 800 = 5000 VA. This is equivalent to 33 amps.</font>
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- <font size="2" face="Verdana, Helvetica, sans-serif">The total load on Phase B is 5 x 800 = 4000 VA. This is equivalent to 42 amps.</font>
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- <font size="2" face="Verdana, Helvetica, sans-serif">This amount of difference in the current in the two Phases (i.e., 9 amps) is not significant. If, for example, the loads are perfectly balanced at one moment in time, and if at that moment your wife turns on an 1200 watt hair dryer, then the current in the phase that powers that hair dryer will exceed the current in the other phase by more than 9 amps.</font>
<font size="2" face="Verdana, Helvetica, sans-serif">I don?t think that the concept of ?evenly proportioned,? as cited in 210.11(B), was intended to be measured and verified to the minutest degree of precision. A reasonable attempt to balance the loads, for example by using breakers from top to bottom and not skipping every other breaker, should be sufficient for code compliance.