An Instantaneous trip only breaker is a magnetic only breaker, i.e. no thermal element, which means it has no long time or short time trip functionality. It looks similar to a molded case circuit breaker. They are used in conjunction with motor overloads, NOT in place of overloads. They would be considered analogous to a fuse, except they can be reset after tripping.
Design Letters and Code Letters are not the same thing. The Code letter in the question relates to Table 430.7(B). As indicated by 430.7(A)(8), by providing a Code Letter, it means the motor is NOT a polyphase wound rotor motor, as this information "shall" be omitted from the nameplate if it is such. Therefore, since it is provided, the maximum Locked Rotor Current is calculated using the Code Letter as follows:
LRC = 7.5Hp x 3.54KVA/Hp x 1000/(230 x 1.73)
LRC = 66.7 A
In selecting the MCP device, as stated earlier, it is based on the full load (continuous) current of the motor, therefore the 22A x 125% = 27.5A would apply, and selection of a 30A MCP would be appropriate. Now, since it is a Code Letter B, the adjustable rating would need to give you some range that the LRC falls between. In looking at the Cutler Hammer Catalog, I would select the device with a lower end of 45A and an upper end of 150A (HMCP).
Obviously, other manufacturers may have different ranges, so you will need to consult your favorite to see what is available that meets your needs.
Regardless, I cannot see how 90A was the answer, I would have selected 70A (for the setting of the MCP). I would agree with others that think the person writing the question may have used some improper terminology thus leading to answer E - None of the Above.