I understand that the 'infinite bus' method is generally considered more conservative, because the actual short circuit current on the output of the transformer will be lower than that given by the infinite bus method.
But aren't there some situations where the higher available short circuit current can result in lower incident energy, because protective devices operate faster? Or do the calculations for incident energy take this into account?
Thanks
Jon
I don’t think so, not in the numbers you see with infinite bus or those with impedance added.
a 10 or a 22kA breaker may try to operate on a large fault but be unable to break the fault if it were, say, about 36kA ASSC.
from a relay perspective, the quickest time will be achieved if the instantaneous pickup is in the trip equation. We do that for personnel protection when someone is working on the circuit, but you never want to leave it like that.
if the curve pickup is the only overcurrent, I doubt the device will open any faster. Were only talking about 8 cycles at max fault