Calculating Total amps across 3 phase using 4 2 phase loads

[Smart $]

Here's mine
sorry but I scribble
converted the loads to a Z
1000/208 = 4.8 A
208/4.8 = 43.3 ohm or 43.3 + 0 j
please check, won't be the first time I made a math or set-up error
won't be the last either lol

Cleaned it up so a non-dyslexic can read it

Well we'd have to be Ant Man to read it on our end. :happyyes:

 

[Ingenieur]

Hmmm

See if this works

 

[Ingenieur]

 

[Smart $]

Hmmm

See if this works

Only 124×280 pixels. I have to assume the server programming is downsizing your image.

Better to use another service (Photobucket, Google Drive, etc.) and link the image into your post.

In the meantime, here is my calc's using actual wattage...

 

[Smart $]

...
In the meantime, here is my calc's using actual wattage...

For 2000W per heater, just double the magnitudes. The angles will remain the same.

 

[Ingenieur]

Only 124×280 pixels. I have to assume the server programming is downsizing your image.

Better to use another service (Photobucket, Google Drive, etc.) and link the image into your post.

In the meantime, here is my calc's using actual wattage...

Got mine to post
there are 8 1000 W heaters
4 a-b
2 b-c
2 c-a

run it with those numbers
it looks like we may match

phase angles for
Iab
Iac
Ica
should be 120 apart since in pararllel with each ph V?

 

[Smart $]

Got mine to post
there are 8 1000 W heaters
4 a-b
2 b-c
2 c-a

run it with those numbers
it looks like we may match

No different than 4 loads at 2000W each...

phase angles for
Iab
Iac
Ica
should be 120 apart since in pararllel with each ph V?

They are... only I am using V_AN as my 0° reference.

 

[Ingenieur]

I had the sign wrong for Ibc
and a math error I think

a 25.4 ang 19
b 25.4 ang 161
c 16.66 ang -90

 

[Smart $]

I had the sign wrong for Ibc
and a math error I think

a 25.4 ang 19
b 25.4 ang 161
c 16.66 ang -90

Looks good. The discrepancy between your angles and mine is you are using V_AC (V_A to some) as 0° reference and reverse angle convention (i.e. clockwise instead of counterclockwise). You'll see what I mean if you take your angles, shift 30 degrees counterclockwise then reverse sign.

 

[cloudfire181]

Thanks for the response to my thread this should help a lot.

 

[tomito]

Do not sum currents, sum loads.
A B C
1,000 1,000
1,000 1,000
1,000 1,000
1,000 1,000

3,000/120 = 25 A
2,000/120 = 16.66 A
accurate enough

Tom

 

[GoldDigger]

tomito:
If you need to format a table like that one, you cannot just use spaces or tabs unless you put the whole table text inside a "CODE" section. Use the "#" formatting button.

  A       B       C
1000    1000
        1000   1000 
1000           1000

Not perfect, but a lot more readable.

 

[tomito]

tomito:
If you need to format a table like that one, you cannot just use spaces or tabs unless you put the whole table text inside a "CODE" section. Use the "#" formatting button.

  A       B       C
1000    1000
        1000   1000 
1000           1000

Not perfect, but a lot more readable.

Thanks! this is what I meant to post:

    A       B      C
  1000    1000
  1000           1000 
          1000   1000
  1000    1000

so...
Phase A = 25 A
Phase B = 25 A
Phase C = 16.66 A