- Thread starter mstephenson
- Start date

- Location
- Waterdown ontario Canada

There is a number of different ways to determine the amount of inductive reactance, - 2*pie*F*L. F-frequency, L-inductance (measured in Henry's). The inductance of an inductor can be calculated like this - inductive reactance / 2*pie*F.

So you can see "via calculations" the higher the inductance of an inductor, and the higher the frequency the more induced voltage (inductive reactance) an inductor will induce. So if we had an inductor with a lower amount of inductance we would need to apply a higher frequency to produce the same amount of inductive reactance opposed to inductor with a higher inductance.

So if you have a inductor that says it should be operated on 400VAC 30hz and 60hz is applied to that specific inductor it will induce a Higher amount of inductive reactance into the circuit, therefor limiting more current then originally intended to operate on.

Please keep in mind that I was talking specifically about the resistance being negligible, inductors to exhibit internal resistance, therefor the total limiting factor would be the %Z. This can be computed using vector addition since the resistance and inductive reactance are usually out of phase.

I tried to keep this as simple as possible without to many calculations, so I'm sorry if this is not understandable.

Scott.

Fixed speed motors, those with starters, will run 20% faster on 60Hz. That may well be a problem. Even a headache.

Those on variable speed drives may be OK

Solenoids will probably be OK - the V/f ration is the same for both systems.

PLC power supplies - again check the spec. on input voltage.

Wiring,I don't know.......