jumper
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Sure, just that sum means addition![]()
So, add the negative since they are voltage drops.
Sure, just that sum means addition![]()
Sure, just that sum means addition![]()
http://www.allaboutcircuits.com/vol_1/chpt_6/2.htmlThis principle is known as Kirchhoff's Voltage Law (discovered in 1847 by Gustav R. Kirchhoff, a German physicist), and it can be stated as such:
"The algebraic sum of all voltages in a loop must equal zero"
Sorry man, you're right. I took Mike Holt's study material and learned it this way, "The sum of the voltage drops equals the applied voltage."
from Mike Holts electrical nec exam prep 2005 pg 51
You were expecting it to be more complicated than it is and had some kind of mind block keeping you from seeing how easy it was.
Really depends on what you call algebra, or an algebra class.True, but I still recommend a basic algebra course.
For example: take the the power circle chart.
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I only need to memorize 2 equations and I can solve questions regarding all 12 through substitution.
E= I*R and P=E*I
A slash rated breaker, rated 277/480 volt,is permitted to be installed in an ungrounded, 480 volt,
three-phase, three-wire panelboard. Key answer False.
I get confused in the wording of 240.85. Went to Art. 100. When they say grounded or ungrounded,
what are they saying by that? Panel's are allway's grounded for protection, not? Then they talk of
nominal voltage, which is the one to consider? Little confused.
Which of the following wiring methods are not permitted when exposed to physical damage?
Key Answ. E
A. Busway
B. EMT
C. IMC
D. RMC
E. LFMC
F. All of the above are permitted.
In the uses not Prem., some say ( physical damage) and some say ( severe physical damage).
I looked in Art 100. So far there Answ. are correct. It took you guy's to show me how they
come up with answer before, so this one has me confused. We all run EMT out of the ground.
Now we get to 300.50 and it say's more. We all run #80 PVC out of the ground.
Interesting.
What minimum size main bonding jumper is required for an 1200 ampere service, supplied by six 3/0
XHHW-2 conductors paralleled per phaes?
A. #2
B. 1/0
C. 3/0
D. 250 kcmil
E. None of these.
Key Answ. C ,Ref. 250.28
I read 250.28, and that is fine. 250.28 talk's about the 12 1/2 percent on the sizing. Now, I went to
to table 250.122 to get the result's. I don't get the 12 1/2 percent, and how we rate it. Mike's
DVD's didn't have much on this.
What minimum size main bonding jumper is required for an 1200 ampere service, supplied by six 3/0
XHHW-2 conductors paralleled per phaes?
A. #2
B. 1/0
C. 3/0
D. 250 kcmil
E. None of these.
Key Answ. C ,Ref. 250.28
I read 250.28, and that is fine. 250.28 talk's about the 12 1/2 percent on the sizing. Now, I went to
to table 250.122 to get the result's. I don't get the 12 1/2 percent, and how we rate it. Mike's
DVD's didn't have much on this.
On the last Ques. of the bonding jumper size, I can't seem to find it Mikes work book? Maybe it was in
DVD'S that he talked about it.
Chap. 9,table 8 show's .173 for area of 3/0. .173x6=1.038. I did that step before I even posted the
thread. Now I am looking at this and saying to myself, I know what to do, but it is not comming to
me. I don't know why I have a mind block on this deal? When I went throught the DVD,S it worked.
Chapter 9 table 8 is for bare conductors. You need to look in the table for the conductor type you are using. Which in your case is XHHW-2, then look under the 3/0. That would be 0.2642.
On the last Ques. of the bonding jumper size, I can't seem to find it Mikes work book? Maybe it was in
DVD'S that he talked about it.
Chap. 9,table 8 show's .173 for area of 3/0. .173x6=1.038.