ATSman
ATSman
- Location
- San Francisco Bay Area
- Occupation
- Electrical Engineer/ Electrical Testing & Controls
180917-2141 EDT
On the subject of switching the coil in a contactor and using rectified AC to power the coil;
My experiment on an AB #2 starter. 709 #2, 709COD 120 V coil.
On AC this solidly pulls in at 70.9 V 0.11 A steady state after pull in.
At 120.7 V current is 0.24 A. DC resistance is 40.5 ohms. Approx power dissipation at 120 is 2.3 W.
Dropout between 65 and 70 V and very noisy.
Powering the same coil with a bridge rectifier.
Pull in at 48.3 V and 1.08 A. Calculated R = 44.7 for a check. Power dissipation 48.3*1.08 = 52 W. With greater voltage, which is necessary for a good operating point, this won't go down.
Dropout is about 6.5 V. and power dissipation at this point about 6.5^2/40.5 = 1.04 W.
With AC you get high current when the armature is open. This provides the force to close the armature, and after closure the impedance goes way up and current drops a great deal. Once the armature is closed it requires much less current to keep it closed.
My above results seem almost unbelievable. But I don't think I made a mistake. Smaller AC relays with a much smaller initial air gap I don't believe show as much disparity between AC and DC. I haven't checked one recently. My recollection was that I could run a 120 V P&B AC relay on 24 V DC.
Possibly someone else will run some experiments.
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Tks GAR for taking the time to do the leg work and explain the difference between the 2 systems.
Based on your results, looks like those Westinghouse engineers back then knew what they were talking about!
I love George W and Nicola T. Thomas E not so much